2016韓國代購網 , 韓國代購化妝品 , 韓國代購批發 , 韓國代購教學---韓國代購/追加/寄貨

答： C 2 * 5^0.5
解：
因 AB = AC 得 三角形 ABC 為等腰三角形，又 角BAC = 90度，得 角B = 角C = ( 180 - 90 ) / 2 = 45 度
由 AB^2 + AC^2 = BC^2 及 AB = AC
得 2 * AB = ( 2 + 6 )^2 ==> 2 * AB^2 = 64 ==> AB = 32^0.5= 4 * 2^0.5
由 P 點引 AB 的垂線，得垂足 Q 。
因 角B = 45 度， 所以 QB = QP，由 三角形PQB 得；
QB^2 + QP^2 = BP^2 ==> 2 * QB = 2^2 ==> QB = QP = 2^0.5
QA = AB - QB = 4 * 2^0.5 - 2^0.5 = 3 * 2^0.5
AP^2 = QA^2 + QP^2 ==> AP^2 = ( 3 * 2^0.5 )^2 + ( 2^0.5 )^2 ==> AP^2 = 9 *2 + 2 = 20
AP = 20^0.5 = 2 * 5^0.5

參考資料： 自己

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